Question 1101465
 find all real solutions to this equation: 
4x^-4 -16x^-2+4 = 0 
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Let w = x^-2
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Substitute to get:
4w^2 - 16w + 4 = 0
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Solve for "w"::
4(w^2 - 4w + 1) = 0
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Quadratic Formula::
w = [4 +- sqrt(16-4*1*1)]/2
w = [4 +- sqrt(12)]/2
w = 2 +- 2sqrt(3)
w = -1.4641 or w = 5.4641
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Ans:: x = 0.1830.. or x = -0.6830..
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Cheers,
Stan H.
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