<PRE><B>Question 1101467</B>
 Find the largest angle in a triangle with sides 6.0 cm, 7.0 cm, and 8.0 cm. 
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The angle opposite the largest side is the largest angle.
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a^2 = b^2 + c^2 - 2bc*Cos(A)
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Cos(A) = [b^2+c^2-a^2]/(2bc)
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Cos(A) = [6^2+7^2-8^2]/(2*6*7) = -0.9167
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A = arccos(-0.9167) = 156.44 degrees
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Cheers,
Stan H.
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