Question 1101402
f(6)=0 means {{{x-6}}} is a factor of f(x).  Use synthetic division to get a quadratic factor.


Do that division, not shown here, and find  {{{f(x)=(x-6)(-2x^2-x+1)}}}, or write this as  {{{f(x)=-(x-6)(2x^2+x-1)}}}.