Question 1101259
If the value decreases exponentially, then:
11987=21028e^-4k; where k is the depreciation constant. So
.57005=e^-4k
ln .57005=5ln e^-4k=-4k ln e=-4k
k=0.140508
Then:
4992/21028=e^-0.140508t
ln 0.2374=ln e^-0.140508t=-0.140508t ln e=-0.140508t
t=10.234 years for the car to be worth $4992
☺☺☺☺