Question 1101119
For the line 3x+2y-5=0, find the obtuse angle the line that makes with the positive direction of the x-axis.
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Step 1, find the slope of the given line.  Call it {{{m[1]}}}
Step 2, lines perpendicular have a slope that's the negative inverse. = {{{-1/m[1]}}}  Call it {{{m[2]}}}
Step 3, use {{{y-y[1] = m[2]*(x - x[1])}}} Where (x1,y1) is the point.
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KNOW how to do this.  It's basic.