Question 1101055
I think Ikleyn and Jorel are interpreting the problem such that:

The trip to Kingston took 2 hours
He spent an hour at his destination doing something.
The problem clearly states, at least now, that the one hour stop is included in the total trip time of 6 hours.
He took 3 hours traveling back home.
2+1+3=6
So Jorel's solution seems right to me.

If the speed going to Kingston is x, then his speed coming back is x-20. So:
2(x)= 3(x-20)
x=60
His speed going to Kingston was 60 kph; his speed going back was 40 kph

60 kph is only 37.2823 mph
40 kph is only 24.8548 mph
He was out for a Sunday drive in the country.