Question 1101096
From the second equation , we get 

y=2x-5. 
Substituting  y=2x-5 in the first equation , we get 
x^2-2x+5=4x 

or, x^2-6x+5=0, 
or, x^2-5x-x+5=0, 
or, (x-5)(x-1)=0, 
or, x=5,1 
If x=5 , then y=5, 
If x=1, then y=-3, Thus the solutions are (5,5) or (1,-3)