Question 1101023


Multiply first by 2 and multiply second equation by 3.
{{{system(4y-6x=26xy,15y+6x=12xy)}}}


{{{19y=38xy}}}
{{{y=2xy}}}
{{{2xy-y=0}}}
{{{y(2x-1)=0}}}
and you can try {{{x=1/2}}} and solve for y using this.

(Seems to give {{{y=-1/3}}} from both original equations)


(Might have one more solution)