Question 1101026
If they are 2-digit numbers, factoring gives the answer quickly.
{{{2000=2*10^3=2^4*5^3}}}
{{{2000=20*100}}} with a 2-digit number and a 3-digit number,
so we need a smallest factor larger than {{{20}}} ,
and it can only have {{{2}}} and {{{5}}} as prime factors.
{{{25}}} and {{{40}}} are the next such smaller factor candidates.
{{{25*80=2000}}} and {{{40*50=2000}}} , but only {{{40+50=90}}} works.
The numbers are {{{highlight(40)}}} and {{{highlight(50)}}} .