Question 1100931
In PRS, segment PT is an altitude and segment PX is a median.

Find RS if RX = x + 7 and SX = 3x – 11

Find RT if RT = x – 6 and PTR = 8x - 6
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1.  Find  RS  if  RX = x + 7  and  SX = 3x – 11 


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a)  Make a sketch to follow my arguments.


b)  Since PX is the median, |RT| = |SX|  (the measures of these segments are the same).

    It gives you an equation'

    x + 7 = 3x - 11  ====>  7 + 11 = 3x - x  ====>  2x = 18  ====>  x = 9.


    Then |RS| = x+7 = 9+7 = 16;  |SX| = 3x-11 = 3*9-11 = 16  (it is not amazing: it should be so !)

         and  |RS| = 16 + 16 = 32.
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2. &nbsp;Find &nbsp;RT &nbsp;if RT = x – 6 &nbsp;and &nbsp;&#61522;PTR = 8x - 6.


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    Honestly, I can not read this:  &#61522;PTR = 8x - 6,

    and do not understand what does it mean.
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In future posts, please do not use this symbol  " &#61522; ", since it is non-standard and its meaning is dark.