Question 1100964
<br>Since the half life is 5730 years, the fraction of the original amount remaining after t years is
{{{(1/2)^(t/5730)}}}<br>
If 94% remains,
{{{(1/2)^(t/5730) = 0.94}}}
{{{(t/5730)*log(.5) = log(0.94)}}}
{{{t/5730 = log(0.94)/(log(.5))}}}
{{{t = 5730*(log(0.94)/log(.5)) = 511.5}}}<br>
The bone is about 511 years old.