Question 1100949
<br>I very much suspect that the equation is supposed to have the first term to the power 3 instead of 2.<br>
As you show the problem, it is not very interesting, or very educational.<br>
But if the first exponent is 3, then there is something to learn from the problem.<br>
So I will answer the question, assuming a power of 3 on the first term.<br>
The equation is then<br>
{{{(x+1)^3 + 3x(x+1)^2 + 3x^2(x+1) + x^3}}}<br>
The expression is in the form of<br>
{{{a^3 + 3a^2b + 3ab^2 + b^3}}} which is equal to {{{(a+b)^3}}}<br>
So the equation is equivalent to<br>
{{{((x+1)+x)^3 = 0}}}
{{{(2x+1)^3 = 0}}}
{{{2x+1 = 0}}}
{{{x = -1/2}}}<br>
The equation has a triple root at x = -1/2.