Question 1100903
The CHANGE in volume when adding the ball:
{{{(4/3)pi*(9.3/2)^3}}}


The CHANGE in height, x:
{{{x*pi*(18/2)^2=(4/3)pi*(9.3/2)^3}}}


{{{x*9^2=(4/3)*(4.65)^3}}}


{{{x=(4/3)4.65^3/81}}}

{{{x=4*4.64^3/27}}}

{{{x=14.9}}}---------ADD this to 13.2 cm.