Question 1100905
<pre>Let x = the first number</pre>The third number is 7 more than the first.<pre>So the third number = x+7</pre>The second number is 4 times the third.<pre>
So the second number = 4(x+7)</pre>The sum of three numbers is 119.<pre>So x + x+7 + 4(x+7) = 118. 

Solve that for x.  It will be the first number
Add 7 to get the third number.  Then multiply
that by 4 to get the second number.

Edwin</pre>