<PRE><B>Question 1100863</B>
&lt;br&gt;You don&#39;t mean combinations here.  In a password, the order of the characters is important.&lt;br&gt;
Assuming &quot;between 0 and 9&quot; means including 0 and 9, there are 10 choices for the digits.&lt;br&gt;
Then we need to...
choose 1 of the 26 letters:  C(26,1) = 26
choose 3 of the 10 digits: C(10,3) = 120
choose 2 of the 5 other characters: C(5,2) = 10&lt;br&gt;
Then, since the statement of the problem did not prescribe any order for all the 6 characters of the password, they can be arranged in 6!=720 different orders.&lt;br&gt;
Then the total number of possible passwords is {{{26*120*10*720 = 224640000}}}&lt;br&gt;
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On reading the problem again, there are several possible interpretations.&lt;br&gt;
The solution above assumes that neither digits nor special characters can be repeated; and it assumes that there is no specified order for the total of 6 characters.&lt;br&gt;
If digits or special characters can be used more than once, then the number of choices is greater; and the number of different arrangements now is complicated by the possibility of repeated characters.&lt;br&gt;
And if there was some unstated condition about the order of the different types of characters, then the whole problem changes.&lt;br&gt;
So the solution I showed my be not at all what you were looking for.&lt;br&gt;
Resubmit the problem if necessary, making it absolutely clear what the requirements for the password are.</PRE>