Question 1100812
Calculate the determinant,
{{{x(2x-3)+1(2-2)+0(3-2x)=-4x}}}
{{{2x^2-3x=-4x}}}
{{{2x^2+x=0}}}
{{{x(2x+1)=0}}}
Two solutions,
{{{x=0}}}
and
{{{2x+1=0}}}
{{{2x=-1}}}
{{{x=-1/2}}}