Question 1100771
From 2,
{{{a=b/8}}}
Substituting into 1,
{{{8/b+b=6}}}
{{{8+b^2=6b}}}
{{{b^2-6b=-8}}}
Complete the square,
{{{b^2-6b+9=-8+9}}}
{{{(b-3)^2=1}}}
{{{b-3=0 +- 1}}}
{{{b=3 +- 1}}}
{{{b=4}}} and {{{b=2}}}
When {{{b=4}}},
{{{a(4)=8}}}
{{{a=2}}}
(2,4)
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When {{{b=2}}}
{{{a(2)=8}}}
{{{a=4}}}
(4,2)
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