Question 1100704
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I'm assuming each die has 6 sides (labeled 1 through 6). 


Let's make one die be red and the other be blue.


Make a table of all the possible sums that we can make (sums are in black ink)


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There are 6*6 = 36 sums in the table. Of which, there are 3 copies of 10 (formed by 4+6=10,5+5=10,6+4=10). So that makes 36-3 = 33 copies that are not a sum of 10. 


Divide the number of copies that aren't ten (33) over the total number of sums (36) to get {{{33/36 = 11/12}}}. Don't forget to reduce as much as possible.


The answer as a fraction is {{{11/12}}}


If you need the answer in decimal form, then use a calculator to get this approximate result {{{11/12=0.9167}}} (rounded to 4 decimal places)
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