Question 1100540
(3x+4/[6x^3+17x^2+27x+20]
========2x^2===3x====5
========6x^3+8x^2, change sign
=============9x^2+27x
=============9x^2+12x, change sign
==================15x+20
==================15x+20, change sign
=======================0
the quotient is 2x^2+3x+5