Question 1100496
Rate x Time = Distance
.
.
.
So for the Jensons,
{{{D[J]=50*T+20}}} since they're already 20 miles ahead.
and for the Allisons,
{{{D[A]=60*T}}}
So find {{{T}}} when,
{{{D[J]=D[A]}}}
{{{50T+20=60T}}}
{{{10T=20}}}
Solve for {{{T}}} in hours.