Question 1100487
<br>The variation equation is
{{{t = (kx)/sqrt(y)}}}<br>
{{{x}}} decreased by 4% is {{{0.96x}}}
{{{sqrt(y)}}} with y increased by 44% is {{{sqrt(1.44y) = 1.2*sqrt(y)}}}<br>
Then the "new" value of t is {{{(0.96kx)/(1.2*sqrt(y)) = 0.8*((kx)/sqrt(y))}}}<br>
The new value of t is 0.8, or 0.80, times the original value; its value has decreased by 20%.