Question 1100228
One to one : Since the sin function is periodic, there are multiple values of x for a given value of y. Therefore it cannot be one to one.
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Onto : There is no x in the domain that will give a value of f(x) such that {{{abs(f(x))>1}}}. So it's not onto.
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If we restrict the domain to [{{{(1/2)pi}}},{{{(3/2)pi}}}] and restrict the co-domain to [{{{-1}}},{{{1}}}].
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*[illustration vc3.JPG].