Question 1100355
{{{5n+10d+25q=315}}}
{{{n+2d+5q=63}}}


{{{q=(n+d)/2}}}
and
{{{n-d=2}}}


Solve this system: {{{system(n+2d+5q=63,n+d=2q,n-d=2)}}}



E2 & E3:
{{{2n=2q+2}}}
{{{n=q+1}}}


E1 & 2E3:
{{{n+2d+5q+2n-2d=63+4}}}
{{{3n+5q=67}}}


Just these two equation results:
{{{system(n=q+1,3n+5q=67)}}}
and substitute for n.
{{{3(q+1)+5q=67}}}
{{{3q+3+5q=67}}}
{{{8q=64}}}
{{{q=8}}}-------and find the others from this value.