<PRE><B>Question 98329</B>
An=9+(n-1)4
To find the first five terms substitute 1, 2, 3, 4 then 5 into the equation in order to find the terms.
eg 
A1=9+(1-1)4=9+0x4=9+0=9
A2=9+(2-1)4=9+1x4=9+4=13
A3=9+(3-1)4=9+2x4=9+8=17
A4=9+(4-1)4=9+3x4=9+12=21
A5=9+(5-1)4=9+4x4=9+16=25

The first five terms are 9, 13, 17, 21 and 25.

An=7+(n-1)(-2)
A1=7+(1-1)(-2)=7+0x(-2)=7+0=7
A2=7+(2-1)(-2)=7+1x(-2)=7+(-2)=5
A3=7+(3-1)(-2)=7+2x(-2)=7+(-4)=3
A4=7+(4-1)(-2)=7+3x(-2)=7+(-6)=1
A5=7+(5-1)(-2)=7+4x(-2)=7+(-8)=-1

The first five terms are 7, 5, 3, 1, -1

Use the same procedure in each of the other sequences.
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