Question 1100280
.
<pre>
From the condition you have these two equations


Home  + Car  + Restaurant = 141   (1)

(Home + Car) - Restaurant =  11   (2)   ("The total number of meals eaten in a car or at home exceeds the number eaten in a restaurant by 11. ")

---------------------------------------Subtract eq(2) from eq(1). You will get

2*Restaurant = 141 - 11 = 130  ==========>  Restaurant = {{{130/2}}} = 65.


Thus one unknown is just found.  It is Restaurant = 65.


Now account that "Ten more&#8203; restaurant-purchased meals will be eaten in a restaurant than at home."


It will give you immediately  Home = Restaurant - 10 = 65 - 10 = 55.


Finally, from eq(1)  Car = 141 - (65+55) = 141 - 120 = 21.
</pre>

<U>Answer</U>.  &nbsp;&nbsp;Home = 55,  &nbsp;&nbsp;Restaurant = 65,  &nbsp;&nbsp;Car = 21.



=============================
Dear turor @richwmiller,


In response to your question,


<H3>I am not obliged to report you</H3>


But if you wish, I can continue in more calm tone:


<pre>
    I did it because I feel that my addition and contribution will be useful.
</pre>

Also, since

<pre>
    - I am quite old and experienced;

    - I have quite good (if not to say "perfect") mathematical education;

    - I learned from the best teachers, from the best textbooks, from the best books-collections of mathematical school problems, 
      advanced problems, Olympiad level problems;

    - I know the school math subjects along and accross;
</pre>

with all of this and because of all of it, I am able to make my decisions  on my own,

without asking your permission and even without asking your opinion, and even in opposite to your opinion.



Also, I am too good tutor (as you said) to tolerate yours invectives against me calling my posts and solutions "trivial".



Sincerely . . .