Question 1100207
There is a formula to help with this, in case a function is not factorable.



(b)
{{{x^2+8x-15}}}
-
{{{x^2+8x+16-16-15}}}, completing the square
{{{(x+4)^2-31}}}


Axis of symmetry, {{{x=-4}}}.
Vertex, (-4,-31).
You can find the desired points yourself.  You should at least include the two x-intercepts.  Solve this equation:   {{{(x+4)^2-31=0}}}.