Question 1099922
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(1)-if 41x is a multiple of 11,where x is a digit what is the value of x<br>
If 41x is a multiple of 11, then x must be a multiple of 11, because 41 is not a multiple of 11.  But there is no digit that is a multiple of 11; unless you allow the trivial case of x=0.<br>
(2)-if 3y5 is a multiple of 11,where y is a digit what is the value of y<br>
I assume this is supposed to be 3y^5.  In that case the answer is the same as for the first problem.  3 is not a multiple of 11, so y^5 must be a multiple of 11, which means y must be a multiple of 11.  Again the only digit for which this is true is the trivial case of y=0.<br>
(3)-if 41z2 is a multiple of 6,where z is a digit what is the value of z<br>
This time there is a solution, assuming the expression is supposed to be 41z^2.  41 is not a multiple of 6; but 6 is.  So for this one the answer is z=6.