Question 1099939
This is a binomial probability problem with 6 trials and P(success) = 0.2
P(0) = C(6,0)*0.2^0*0.8^6 = 0.262
P(1) = C(6,1)*0.2^1*0.8^5 = 0.393
Therefore the probability of getting less than 2 correct is 0.393 + 0.262 = 0.655