<PRE><B>Question 1099859</B>
42 - q = q - 2
add 2 to both sides
44-q=q
add q to both sides
44=2q
q=22 quarters
22 q=$5.50
42-22=20 more coins
7.10-5.50=$1.60
160=5n+10d
n+d=20
n=20-d
160=5(20-d)+10d
160=100-5d+10d
60=5d
d=12 dimes
n=8 nickels
q=22 quarters
22=12+8+2

22*.25=5.50
8*.05=.40
12*.10=1.20
5.50+.40+1.20=7.10
12+8+22=42
The sum of the numbers of nickels and dimes (20) is 2 LESS than the number of quarters (22)
20 is less than 22

ok

checking other tutors answers
20 quarters, 20 dimes and 2 nickels
20 *.25=5.00
20 *.10=2.00
2 *.05=.10
5.00+2.00+.10=$7.10 ok
The sum of the numbers of nickels and dimes (22) is 2 LESS (not more) than the number of quarters (20)
22 is more than 20
20 quarters, 20 dimes and 2 nickels does NOT satisfy the condition.









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