Question 1099459






<pre>
{{{drawing(250,400,-5,5,-10,6,

line(-4.378,0,0,4.668), line(0,4.668,4.378,0), 
line(-4.378,0,0,-8.656), line(0,-8.656,4.378,0),
line(0,4.668,0,-8.656), arc(4.378,0,4,-4,133,243),
locate(2.7,.2,"110°"),locate(2.3,2.9,6.4),locate(2.5,-4,9.7),
locate(-.1,5.3,A),locate(-4.9,.25,B)locate(-.3,-8.6,C), 
locate(4.55,.25,D) 
 )}}}

To find the area of triangle ADC, we can use the formula:

"The area of a triangle is one-half the product of two
sides multiplied by the sine of the angle between those
two sides."

So,

{{{matrix(1,3,
Area,""="",expr(1/2)*AD*DC*sin("<ADC"))}}}

Calculate that with what you're given and then multiply what
you get by 2 since the area of the kite is twice the area of 
triangle ADC.

Edwin</pre><b>