Question 1099794
{{{abs(-2AB)=48}}}
{{{abs(B)=2}}}
You also know that,
{{{abs(AB)=abs(A)*abs(B)}}}
and
{{{abs(kA)=k^n*abs(A)}}}
So then,
{{{abs(AB)=12}}}
and
{{{abs(A)=abs(AB)/abs(B)}}}
{{{abs(A)=12/2}}}
{{{abs(A)=6}}}