Question 98223
i am assuming that you meant the question to be 

{{{sqrt(4x+4) -12 =0}}}
={{{sqrt(4(x+1)) -12 =0 }}}
={{{ 2* sqrt(x+1) = 12}}}
={{{ sqrt(x+1) =6 }}}
={{{(x+1) =36}}}
{{{x=35}}}