Question 98248
{{{K(v)= (4v^2-9)/(v^2-v-90)}}}
The domain of the function is such that expression in the denominator is non zero

{{{(v^2 - v -90) != 0}}}
{{{(v-10)(v+9) !=0}}}
{{{v!=-9  and   v!=10}}}
so the domain of the function is the set of all Real numbers except {-9,10}

i.e.  R - {-9,10} where R is the set of Real numbers