<PRE><B>Question 1099646</B>
A company has five applicants for two positions: two women and three men. Suppose that the five applicants are equally qualified and that no preference is given for choosing either gender. Let X equal to the number of women chosen to fill thbe two positions. 
a) Write down the appropriate probability distribution with its parameters?
binomial probability distribution
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b) What are the mean and variance of this distribution? 
The mean= n*p = 2*(2/5) = 4/5 = 0.8
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The standard deviation= sqrt(n*p*q) = sqrt(.8(3/5))) =  0.6928
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c) What is the probability that a company will hire exactly one woman?
P(x = 1) = binompdf(2,2/5,1) = 0.48
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Cheers,
Stan H.
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