Question 1099730
y^2=25-x^2
2ydy/dx=-2x
dy/dx=-x/y

when x=3, y'=-3/4
use point slope formula y-y1=m(x-x1), m slope and (x1, y1) point.
y-4=(-3/4)(x-3)
y=(-3/4)x+6.25
{{{graph(300,300,-10,10,-10,10,sqrt(25-x^2),-sqrt(25-x^2),(-3/4)x+6.25)}}}