Question 1099680
set y = h(x) and you get:


y = -32x^2 / 720^2 + x + 1488


when you set y equal to 0, the formula becomes:


-32x^2 / 720^2 + x + 1488 = 0


this is a quadratic equation in standard form of ax^2 + bx + x = 0


therefore a = -32/720^2 and b = 1 and c =1488.


use the quadratic formula to solve this equation.


the formula states that:


x = (-b - sqrt(b^2 - 4ac)) / (2a) 


or:


x = (-b + sqrt(b^2 - 4ac)) / (2a) 


from there, it's a simple matter of replacing a,b,c with their respective values.


you will get:


x = (-1 - sqrt(1^2 - 4 * -32/720^2 * 1488)) / (2 * -32/720^2) 


or:


x = (-1 + sqrt(1^2 - 4 * -32/720^2 * 1488)) / (2 * -32/720^2) 


this becomes:


x = 17571.83192


or:


x = -1371.831924


if you have good graphing software, like the one found at <a href = "https://www.desmos.com/calculator" target = "_blank">https://www.desmos.com/calculator</a>, then you can graph the equation of y = -32x^2 / 720^2 + x + 1488 and you will get what is shown below after adjusting the x and y limits correctly.


<img src = "http://theo.x10hosting.com/2017/103101.jpg" alt="$$$" >