Question 1099398
 Y = 2x^2 + 4x
A quadratic equation, min occurs on the axis of symmetry which we can find:
x = -b/(2a), where a=2 and b=4
x = {{{(-4)/(2*2)}}}
x = -1 is axis of symmetry
Find y when x=1
y = 2(-1^2) + 4(-1)
y = 2 - 4
y = -2
coordinates of the turning point -1,-2
Graphing the equation shows the same thing

{{{ graph( 300, 300, -5, 5, -5, 5, 2x^2+4x) }}}