Question 1099422
<pre>
h(x)=x³+8x²+14x+4

Since -2 is a zero we can form this synthetic division
and get 0 remainder

-2|1  8  14  4
  |<u>  -2 -12 -4</u>
   1  6   2  0

And that means that h(x) factors this way

h(x) = (x+2)(x²+6x+2)

       x+2 = 0;      x²+6x+2 = 0
         x = -2;           {{{x = (-6 +- sqrt(6^2-4(1)2)))/(2*1)}}} 
                           {{{x = (-6 +- sqrt(36-8)))/2}}}
                           {{{x = (-6 +- sqrt(28)))/2}}}   
                           {{{x = (-6 +- sqrt(4*7)))/2}}}
                           {{{x = (-6 +- 2sqrt(7)))/2}}}
                           {{{x = (-6)/2 +- 2sqrt(2)/2}}}
                           {{{x = -3 +- sqrt(7)}}}  

The other zeros are {{{-3+sqrt(7)}}} and  {{{-3-sqrt(7)}}}. 
          
Edwin</pre>