Question 1099384
<pre>
               SPEED       TIME        DISTANCE
FAST           50          2             d
SLOW           r           2+1&1/3       d
</pre>


FAST train data will give the distance.
SLOW train data will allow to find speed r of the slow train.


{{{r(2+1&1/3)=50*2}}}

-

{{{r(3&1/3)=100}}}

{{{(10/3)r=100}}}

{{{r=100(3/10)}}}

{{{highlight(r=30)}}}------speed of slow train, 30 mph.