Question 1099335
{{{27k^3-8m^3}}}

{{{(3k)^3-(2m)^3}}}

{{{(3k-2m)((3k)^2+6km+(2m)^2)}}}, using Difference Of Cubes formula

{{{(3k-2m)(9k^2+6km+4m^2)}}}

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You can factor out a 2m and make it 2m,...
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{{{54k^3m-16m^3}}}---------your including the m on the first term was assumed to be a mistake
{{{2m(27k^3-8m^2)}}}----not any more you can do with this.