Question 1099331
If the side opposite {{{ alpha }}} is {{{ a }}} and {{{ b }}} is
the side adjacent to {{{ alpha }}} and
the hypotenuse is {{{ c }}},
{{{ sin( alpha ) = a/c }}}
{{{ a/c = 3/(2*sqrt(6) ) }}}
{{{ b^2 = c^2 - a^2 }}}
{{{ b^2 = ( 2*sqrt(6) )^2 - 3^2 }}}
{{{ b^2 = 4*6 - 9 }}}
{{{ b^2 = 24 - 9 }}}
{{{ b^2 = 15 }}}
{{{ b = sqrt( 15 ) }}}
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{{{ tan( alpha ) = a/b }}}
{{{ tan( alpha ) = 3/sqrt(15) }}}
Notice that you don't need to find the angle {{{ alpha }}}