Question 1099156
{{{S=K+3}}}
Four years ago,
{{{(S-4)+(K-4)=67}}}
{{{S+K-8=67}}}
{{{S+K=75}}}
Substituting,
{{{K+3+K=75}}}
{{{2K=72}}}
Solve for K then use either equation to solve for S.