Question 1099120
Let the 3 consecvutive odd integers be
{{{ n }}}. {{{ n+2 }}}, and {{{ n+4 }}}
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{{{ 3*( n + 2 ) = n + ( n+4 ) - 1 }}}
{{{ 3n + 6 = n + n + 4 - 1 }}}
{{{ 3n - 2n = 4 - 1 - 6 }}}
{{{ n = -3 }}}
and
{{{ n+2 = -1 }}}
and
{{{ n + 4 = 1 }}}
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The consecutive odd integers are:
-3, -1 and 1 
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check:
{{{ 3*(-1) = -3 + 1 - 1 }}}
{{{ -3 = -3 }}}
OK
get a 2nd opinion if needed