Question 1099131
Use Cramer's rule,
{{{A=(matrix(3,3,
1,1,1,
2,-1,3,
4,5,-10))}}}
{{{abs(A)=41}}}
.
.
.
{{{A[x1]=(matrix(3,3,
6,1,1,
4,-1,3,
13,5,-10))}}}
{{{abs(A[x1])=82}}}
.
.
.

{{{A[x2]=(matrix(3,3,
1,6,1,
2,4,3,
4,13,-10))}}}
{{{abs(A[x2])=123}}}
.
.
.

{{{A[x3]=(matrix(3,3,
1,1,6,
2,-1,4,
4,5,13))}}}
{{{abs(A[x3])=41}}}
.
.
.
{{{x[1]=abs(A[x1])/abs(A)=82/41=2}}}
.
.
{{{x[2]=abs(A[x2])/abs(A)=123/41=3}}}
.
.
{{{x[3]=abs(A[x3])/abs(A)=41/41=1}}}