<PRE><B>Question 1099107</B>
derive the equation of a circle which passes through the point A(-2,1), its tangent to the line 3x-2y-6=0 at the point B(4,3)
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Step 1, find the equation of the line perpendicular to the given line thru the point (4,3) --- point B
The center is on that line.
Step 2, find the perpendicular bisector of AB.
The center is on that line, too.
The center is the intersection of the 2 lines.
r is the distance from the center to either point.
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