Question 1099101
Taz is 5 years older than his brother and 
t = b + 5
1 year younger than his cousin.
t = c - 1
t = t therefore
c - 1 = b + 5
c = b + 6
:
 His uncle is 3 times the age of his cousin
u = 3c
 and 4 times the age of his brother.
u = 4b
u = u therefore
4b = 3c
b = {{{3/4}}}c
:
In the equation c = b + 6, replace b with {{{3/4}}}c
c = {{{3/4}}}c + 6
multiply equation by 4 to get rid of the fraction, we have then:
4c = 3c + 24
4c - 3c = 24
c = 24 yrs is the cousin's age
:
 How old is Taz?
t = c - 1
t = 23 yrs is Taz's age