<PRE><B>Question 1099031</B>
 The surface area and diagonal of a cuboid are 288 sq.cm and 12 cm respectively.
 Show that the cuboid is a cube. 
:
let s = one side of the cube
therefore the surface area
6s^2 = 288
s^2 = 288/6
s^2 = 48
:
The diagonal of one side
d = {{{sqrt(2s^2)}}}
The diagonal of the cuboid
{{{sqrt(2s^2 + s^2)}}} = 12
square both side
{{{2s^2 + s^2}}} = 144 
replace s^2 with 48 
{{{(2(48)) + 48)}}} = 144
96 = 144 - 48
96=96</PRE>