Question 1098995
{{{ 2x^2 - 6x + 8 }}}
I can factor out {{{ 2 }}}
{{{ 2*( x^2 - 3x + 4 ) }}}
Use the quadratic formula
{{{ x = ( -b +- sqrt( b^2 - 4*a*c )) / ( 2a ) }}}
{{{ a = 1 }}}
{{{ b = -3 }}}
{{{ c = 4 }}}
{{{ x = ( -(-3) +- sqrt( 9 - 4*1*4 )) / 2 }}}
{{{ x = ( 3 +- sqrt( -7 ) ) / 2 }}}
{{{ x = ( 3 + sqrt(7)*i )/2 }}}
and
{{{ x = ( 3 - sqrt(7)*i )/2 }}}
The factors are:
{{{ 2*(( x + 3 + sqrt(7)*i ) / 2 )*(( x - 3 + sqrt(7)*i )/2 ) }}}
You can multiply this out to check.