Question 1098992
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Log3(x+1)=log3(x-1)+1
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<pre>
{{{log(3,(x+1))}}} = {{{log(3,(x-1))}}} + 1  ====>

x + 1 = 3*(x-1)  ====>  x+1 = 3x - 3  ====>  1+3 = 2x  ====>  x = {{{4/2}}} = 2.


<U>Answer</U>.  x = 2.
</pre>

Solved.