Question 1098990
The original amount of silt was,
{{{5(10/100)=50/100=0.5}}}{{{ft^3}}}
Now there is,
{{{0.5+1=1.5}}}{{{ft^3}}} of silt
And there is a total of {{{5+1=6}}} mixture.
So the new concentration is,
{{{C=((3/2)/6)*100}}}
Work that out for the answer.